How do i convert this curl command:
curl -X POST http://127.0.0.1:18082/json_rpc -d '{"jsonrpc":"2.0","id":"0","method":"getbalance"}' -H 'Content-Type: application/json'
Into a normal http url?
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1 Answer
The HTTP url is: http://127.0.0.1:18082/json_rpc
When you mean with HTTP url, a url that you can type into your browser, than its not possible to achieve the same request with only the HTTP url. Alternative to curl you could use the chrome App Postman to play around with the json_rpc api. Postman
Post is the called HTTP method.
The -d is the payload, in this case the data that is send as Post request to that HTTP url.
The -H defines a HTTP header that is also send. In this case "Content-Type" is set, it describes the format the POST data is in. Its JSON.
Here is more information about curl. Link
