Let's take we have two transactions. In the first transaction, it has 1 input with zero mixins and 3 outputs(stealth addresses). The second transaction has 1 input with one mixins and 2 outputs. Here 1st transaction input is can easily identify as real input being spent because it is zero mixin. Let's assume in the second transaction which has two mixins inside the input. In that one is a mixin and another one is the real one being spent.
My question is if the second transaction input contains the first transaction one output as mixin (one of two), is that mean that is only a decoy for mixins? Can't it be actual spent one in the transaction? Like Bitcoin, chaining the inputs and outputs?
In other word, if in one mixin input (has two ring members), if one is ring member is traceable due to it include transaction used zero mixin. Is that mean remaining ring member is the actual one?